\(\int \frac {1}{x^3 \sqrt {b \sqrt [3]{x}+a x}} \, dx\) [156]

Optimal result

Integrand size = 19, antiderivative size = 388 \[ \int \frac {1}{x^3 \sqrt {b \sqrt [3]{x}+a x}} \, dx=-\frac {154 a^{7/2} \left (b+a x^{2/3}\right ) \sqrt [3]{x}}{65 b^4 \left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right ) \sqrt {b \sqrt [3]{x}+a x}}-\frac {6 \sqrt {b \sqrt [3]{x}+a x}}{13 b x^{7/3}}+\frac {22 a \sqrt {b \sqrt [3]{x}+a x}}{39 b^2 x^{5/3}}-\frac {154 a^2 \sqrt {b \sqrt [3]{x}+a x}}{195 b^3 x}+\frac {154 a^3 \sqrt {b \sqrt [3]{x}+a x}}{65 b^4 \sqrt [3]{x}}+\frac {154 a^{13/4} \left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right ) \sqrt {\frac {b+a x^{2/3}}{\left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right )^2}} \sqrt [6]{x} E\left (2 \arctan \left (\frac {\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right )|\frac {1}{2}\right )}{65 b^{15/4} \sqrt {b \sqrt [3]{x}+a x}}-\frac {77 a^{13/4} \left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right ) \sqrt {\frac {b+a x^{2/3}}{\left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right )^2}} \sqrt [6]{x} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right ),\frac {1}{2}\right )}{65 b^{15/4} \sqrt {b \sqrt [3]{x}+a x}} \]

[Out]

-154/65*a^(7/2)*(b+a*x^(2/3))*x^(1/3)/b^4/(x^(1/3)*a^(1/2)+b^(1/2))/(b*x^(1/3)+a*x)^(1/2)-6/13*(b*x^(1/3)+a*x)
^(1/2)/b/x^(7/3)+22/39*a*(b*x^(1/3)+a*x)^(1/2)/b^2/x^(5/3)-154/195*a^2*(b*x^(1/3)+a*x)^(1/2)/b^3/x+154/65*a^3*
(b*x^(1/3)+a*x)^(1/2)/b^4/x^(1/3)+154/65*a^(13/4)*x^(1/6)*(cos(2*arctan(a^(1/4)*x^(1/6)/b^(1/4)))^2)^(1/2)/cos
(2*arctan(a^(1/4)*x^(1/6)/b^(1/4)))*EllipticE(sin(2*arctan(a^(1/4)*x^(1/6)/b^(1/4))),1/2*2^(1/2))*(x^(1/3)*a^(
1/2)+b^(1/2))*((b+a*x^(2/3))/(x^(1/3)*a^(1/2)+b^(1/2))^2)^(1/2)/b^(15/4)/(b*x^(1/3)+a*x)^(1/2)-77/65*a^(13/4)*
x^(1/6)*(cos(2*arctan(a^(1/4)*x^(1/6)/b^(1/4)))^2)^(1/2)/cos(2*arctan(a^(1/4)*x^(1/6)/b^(1/4)))*EllipticF(sin(
2*arctan(a^(1/4)*x^(1/6)/b^(1/4))),1/2*2^(1/2))*(x^(1/3)*a^(1/2)+b^(1/2))*((b+a*x^(2/3))/(x^(1/3)*a^(1/2)+b^(1
/2))^2)^(1/2)/b^(15/4)/(b*x^(1/3)+a*x)^(1/2)

Rubi [A] (verified)

Time = 0.34 (sec) , antiderivative size = 388, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.368, Rules used = {2043, 2050, 2057, 335, 311, 226, 1210} \[ \int \frac {1}{x^3 \sqrt {b \sqrt [3]{x}+a x}} \, dx=-\frac {77 a^{13/4} \sqrt [6]{x} \left (\sqrt {a} \sqrt [3]{x}+\sqrt {b}\right ) \sqrt {\frac {a x^{2/3}+b}{\left (\sqrt {a} \sqrt [3]{x}+\sqrt {b}\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right ),\frac {1}{2}\right )}{65 b^{15/4} \sqrt {a x+b \sqrt [3]{x}}}+\frac {154 a^{13/4} \sqrt [6]{x} \left (\sqrt {a} \sqrt [3]{x}+\sqrt {b}\right ) \sqrt {\frac {a x^{2/3}+b}{\left (\sqrt {a} \sqrt [3]{x}+\sqrt {b}\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right )|\frac {1}{2}\right )}{65 b^{15/4} \sqrt {a x+b \sqrt [3]{x}}}-\frac {154 a^{7/2} \sqrt [3]{x} \left (a x^{2/3}+b\right )}{65 b^4 \left (\sqrt {a} \sqrt [3]{x}+\sqrt {b}\right ) \sqrt {a x+b \sqrt [3]{x}}}+\frac {154 a^3 \sqrt {a x+b \sqrt [3]{x}}}{65 b^4 \sqrt [3]{x}}-\frac {154 a^2 \sqrt {a x+b \sqrt [3]{x}}}{195 b^3 x}+\frac {22 a \sqrt {a x+b \sqrt [3]{x}}}{39 b^2 x^{5/3}}-\frac {6 \sqrt {a x+b \sqrt [3]{x}}}{13 b x^{7/3}} \]

[In]

Int[1/(x^3*Sqrt[b*x^(1/3) + a*x]),x]

[Out]

(-154*a^(7/2)*(b + a*x^(2/3))*x^(1/3))/(65*b^4*(Sqrt[b] + Sqrt[a]*x^(1/3))*Sqrt[b*x^(1/3) + a*x]) - (6*Sqrt[b*
x^(1/3) + a*x])/(13*b*x^(7/3)) + (22*a*Sqrt[b*x^(1/3) + a*x])/(39*b^2*x^(5/3)) - (154*a^2*Sqrt[b*x^(1/3) + a*x
])/(195*b^3*x) + (154*a^3*Sqrt[b*x^(1/3) + a*x])/(65*b^4*x^(1/3)) + (154*a^(13/4)*(Sqrt[b] + Sqrt[a]*x^(1/3))*
Sqrt[(b + a*x^(2/3))/(Sqrt[b] + Sqrt[a]*x^(1/3))^2]*x^(1/6)*EllipticE[2*ArcTan[(a^(1/4)*x^(1/6))/b^(1/4)], 1/2
])/(65*b^(15/4)*Sqrt[b*x^(1/3) + a*x]) - (77*a^(13/4)*(Sqrt[b] + Sqrt[a]*x^(1/3))*Sqrt[(b + a*x^(2/3))/(Sqrt[b
] + Sqrt[a]*x^(1/3))^2]*x^(1/6)*EllipticF[2*ArcTan[(a^(1/4)*x^(1/6))/b^(1/4)], 1/2])/(65*b^(15/4)*Sqrt[b*x^(1/
3) + a*x])

Rule 226

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b/a, 4]}, Simp[(1 + q^2*x^2)*(Sqrt[(a + b*x^4)/(a*(
1 + q^2*x^2)^2)]/(2*q*Sqrt[a + b*x^4]))*EllipticF[2*ArcTan[q*x], 1/2], x]] /; FreeQ[{a, b}, x] && PosQ[b/a]

Rule 311

Int[(x_)^2/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b/a, 2]}, Dist[1/q, Int[1/Sqrt[a + b*x^4], x],
x] - Dist[1/q, Int[(1 - q*x^2)/Sqrt[a + b*x^4], x], x]] /; FreeQ[{a, b}, x] && PosQ[b/a]

Rule 335

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = Denominator[m]}, Dist[k/c, Subst[I
nt[x^(k*(m + 1) - 1)*(a + b*(x^(k*n)/c^n))^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0]
&& FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 1210

Int[((d_) + (e_.)*(x_)^2)/Sqrt[(a_) + (c_.)*(x_)^4], x_Symbol] :> With[{q = Rt[c/a, 4]}, Simp[(-d)*x*(Sqrt[a +
c*x^4]/(a*(1 + q^2*x^2))), x] + Simp[d*(1 + q^2*x^2)*(Sqrt[(a + c*x^4)/(a*(1 + q^2*x^2)^2)]/(q*Sqrt[a + c*x^4
]))*EllipticE[2*ArcTan[q*x], 1/2], x] /; EqQ[e + d*q^2, 0]] /; FreeQ[{a, c, d, e}, x] && PosQ[c/a]

Rule 2043

Int[(x_)^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)
/n] - 1)*(a*x^Simplify[j/n] + b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, j, m, n, p}, x] &&  !IntegerQ[p] && NeQ[
n, j] && IntegerQ[Simplify[j/n]] && IntegerQ[Simplify[(m + 1)/n]] && NeQ[n^2, 1]

Rule 2050

Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> Simp[c^(j - 1)*(c*x)^(m - j +
1)*((a*x^j + b*x^n)^(p + 1)/(a*(m + j*p + 1))), x] - Dist[b*((m + n*p + n - j + 1)/(a*c^(n - j)*(m + j*p + 1))
), Int[(c*x)^(m + n - j)*(a*x^j + b*x^n)^p, x], x] /; FreeQ[{a, b, c, m, p}, x] &&  !IntegerQ[p] && LtQ[0, j,
n] && (IntegersQ[j, n] || GtQ[c, 0]) && LtQ[m + j*p + 1, 0]

Rule 2057

Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> Dist[c^IntPart[m]*(c*x)^FracPa
rt[m]*((a*x^j + b*x^n)^FracPart[p]/(x^(FracPart[m] + j*FracPart[p])*(a + b*x^(n - j))^FracPart[p])), Int[x^(m
+ j*p)*(a + b*x^(n - j))^p, x], x] /; FreeQ[{a, b, c, j, m, n, p}, x] &&  !IntegerQ[p] && NeQ[n, j] && PosQ[n
- j]

Rubi steps \begin{align*} \text {integral}& = 3 \text {Subst}\left (\int \frac {1}{x^7 \sqrt {b x+a x^3}} \, dx,x,\sqrt [3]{x}\right ) \\ & = -\frac {6 \sqrt {b \sqrt [3]{x}+a x}}{13 b x^{7/3}}-\frac {(33 a) \text {Subst}\left (\int \frac {1}{x^5 \sqrt {b x+a x^3}} \, dx,x,\sqrt [3]{x}\right )}{13 b} \\ & = -\frac {6 \sqrt {b \sqrt [3]{x}+a x}}{13 b x^{7/3}}+\frac {22 a \sqrt {b \sqrt [3]{x}+a x}}{39 b^2 x^{5/3}}+\frac {\left (77 a^2\right ) \text {Subst}\left (\int \frac {1}{x^3 \sqrt {b x+a x^3}} \, dx,x,\sqrt [3]{x}\right )}{39 b^2} \\ & = -\frac {6 \sqrt {b \sqrt [3]{x}+a x}}{13 b x^{7/3}}+\frac {22 a \sqrt {b \sqrt [3]{x}+a x}}{39 b^2 x^{5/3}}-\frac {154 a^2 \sqrt {b \sqrt [3]{x}+a x}}{195 b^3 x}-\frac {\left (77 a^3\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {b x+a x^3}} \, dx,x,\sqrt [3]{x}\right )}{65 b^3} \\ & = -\frac {6 \sqrt {b \sqrt [3]{x}+a x}}{13 b x^{7/3}}+\frac {22 a \sqrt {b \sqrt [3]{x}+a x}}{39 b^2 x^{5/3}}-\frac {154 a^2 \sqrt {b \sqrt [3]{x}+a x}}{195 b^3 x}+\frac {154 a^3 \sqrt {b \sqrt [3]{x}+a x}}{65 b^4 \sqrt [3]{x}}-\frac {\left (77 a^4\right ) \text {Subst}\left (\int \frac {x}{\sqrt {b x+a x^3}} \, dx,x,\sqrt [3]{x}\right )}{65 b^4} \\ & = -\frac {6 \sqrt {b \sqrt [3]{x}+a x}}{13 b x^{7/3}}+\frac {22 a \sqrt {b \sqrt [3]{x}+a x}}{39 b^2 x^{5/3}}-\frac {154 a^2 \sqrt {b \sqrt [3]{x}+a x}}{195 b^3 x}+\frac {154 a^3 \sqrt {b \sqrt [3]{x}+a x}}{65 b^4 \sqrt [3]{x}}-\frac {\left (77 a^4 \sqrt {b+a x^{2/3}} \sqrt [6]{x}\right ) \text {Subst}\left (\int \frac {\sqrt {x}}{\sqrt {b+a x^2}} \, dx,x,\sqrt [3]{x}\right )}{65 b^4 \sqrt {b \sqrt [3]{x}+a x}} \\ & = -\frac {6 \sqrt {b \sqrt [3]{x}+a x}}{13 b x^{7/3}}+\frac {22 a \sqrt {b \sqrt [3]{x}+a x}}{39 b^2 x^{5/3}}-\frac {154 a^2 \sqrt {b \sqrt [3]{x}+a x}}{195 b^3 x}+\frac {154 a^3 \sqrt {b \sqrt [3]{x}+a x}}{65 b^4 \sqrt [3]{x}}-\frac {\left (154 a^4 \sqrt {b+a x^{2/3}} \sqrt [6]{x}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {b+a x^4}} \, dx,x,\sqrt [6]{x}\right )}{65 b^4 \sqrt {b \sqrt [3]{x}+a x}} \\ & = -\frac {6 \sqrt {b \sqrt [3]{x}+a x}}{13 b x^{7/3}}+\frac {22 a \sqrt {b \sqrt [3]{x}+a x}}{39 b^2 x^{5/3}}-\frac {154 a^2 \sqrt {b \sqrt [3]{x}+a x}}{195 b^3 x}+\frac {154 a^3 \sqrt {b \sqrt [3]{x}+a x}}{65 b^4 \sqrt [3]{x}}-\frac {\left (154 a^{7/2} \sqrt {b+a x^{2/3}} \sqrt [6]{x}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {b+a x^4}} \, dx,x,\sqrt [6]{x}\right )}{65 b^{7/2} \sqrt {b \sqrt [3]{x}+a x}}+\frac {\left (154 a^{7/2} \sqrt {b+a x^{2/3}} \sqrt [6]{x}\right ) \text {Subst}\left (\int \frac {1-\frac {\sqrt {a} x^2}{\sqrt {b}}}{\sqrt {b+a x^4}} \, dx,x,\sqrt [6]{x}\right )}{65 b^{7/2} \sqrt {b \sqrt [3]{x}+a x}} \\ & = -\frac {154 a^{7/2} \left (b+a x^{2/3}\right ) \sqrt [3]{x}}{65 b^4 \left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right ) \sqrt {b \sqrt [3]{x}+a x}}-\frac {6 \sqrt {b \sqrt [3]{x}+a x}}{13 b x^{7/3}}+\frac {22 a \sqrt {b \sqrt [3]{x}+a x}}{39 b^2 x^{5/3}}-\frac {154 a^2 \sqrt {b \sqrt [3]{x}+a x}}{195 b^3 x}+\frac {154 a^3 \sqrt {b \sqrt [3]{x}+a x}}{65 b^4 \sqrt [3]{x}}+\frac {154 a^{13/4} \left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right ) \sqrt {\frac {b+a x^{2/3}}{\left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right )^2}} \sqrt [6]{x} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right )|\frac {1}{2}\right )}{65 b^{15/4} \sqrt {b \sqrt [3]{x}+a x}}-\frac {77 a^{13/4} \left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right ) \sqrt {\frac {b+a x^{2/3}}{\left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right )^2}} \sqrt [6]{x} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right )|\frac {1}{2}\right )}{65 b^{15/4} \sqrt {b \sqrt [3]{x}+a x}} \\ \end{align*}

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 10.05 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.15 \[ \int \frac {1}{x^3 \sqrt {b \sqrt [3]{x}+a x}} \, dx=-\frac {6 \sqrt {1+\frac {a x^{2/3}}{b}} \operatorname {Hypergeometric2F1}\left (-\frac {13}{4},\frac {1}{2},-\frac {9}{4},-\frac {a x^{2/3}}{b}\right )}{13 x^2 \sqrt {b \sqrt [3]{x}+a x}} \]

[In]

Integrate[1/(x^3*Sqrt[b*x^(1/3) + a*x]),x]

[Out]

(-6*Sqrt[1 + (a*x^(2/3))/b]*Hypergeometric2F1[-13/4, 1/2, -9/4, -((a*x^(2/3))/b)])/(13*x^2*Sqrt[b*x^(1/3) + a*
x])

Maple [A] (verified)

Time = 3.26 (sec) , antiderivative size = 262, normalized size of antiderivative = 0.68

method	result	size
derivativedivides	\(-\frac {6 \sqrt {b \,x^{\frac {1}{3}}+a x}}{13 b \,x^{\frac {7}{3}}}+\frac {22 a \sqrt {b \,x^{\frac {1}{3}}+a x}}{39 b^{2} x^{\frac {5}{3}}}-\frac {154 a^{2} \sqrt {b \,x^{\frac {1}{3}}+a x}}{195 b^{3} x}+\frac {154 \left (b +a \,x^{\frac {2}{3}}\right ) a^{3}}{65 b^{4} \sqrt {x^{\frac {1}{3}} \left (b +a \,x^{\frac {2}{3}}\right )}}-\frac {77 a^{3} \sqrt {-a b}\, \sqrt {\frac {\left (x^{\frac {1}{3}}+\frac {\sqrt {-a b}}{a}\right ) a}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x^{\frac {1}{3}}-\frac {\sqrt {-a b}}{a}\right ) a}{\sqrt {-a b}}}\, \sqrt {-\frac {x^{\frac {1}{3}} a}{\sqrt {-a b}}}\, \left (-\frac {2 \sqrt {-a b}\, E\left (\sqrt {\frac {\left (x^{\frac {1}{3}}+\frac {\sqrt {-a b}}{a}\right ) a}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{a}+\frac {\sqrt {-a b}\, F\left (\sqrt {\frac {\left (x^{\frac {1}{3}}+\frac {\sqrt {-a b}}{a}\right ) a}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{a}\right )}{65 b^{4} \sqrt {b \,x^{\frac {1}{3}}+a x}}\)	\(262\)
default	\(\frac {-462 a^{3} b \sqrt {\frac {a \,x^{\frac {1}{3}}+\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (a \,x^{\frac {1}{3}}-\sqrt {-a b}\right )}{\sqrt {-a b}}}\, \sqrt {-\frac {x^{\frac {1}{3}} a}{\sqrt {-a b}}}\, x^{\frac {10}{3}} \sqrt {x^{\frac {1}{3}} \left (b +a \,x^{\frac {2}{3}}\right )}\, E\left (\sqrt {\frac {a \,x^{\frac {1}{3}}+\sqrt {-a b}}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )+231 a^{3} b \sqrt {\frac {a \,x^{\frac {1}{3}}+\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (a \,x^{\frac {1}{3}}-\sqrt {-a b}\right )}{\sqrt {-a b}}}\, \sqrt {-\frac {x^{\frac {1}{3}} a}{\sqrt {-a b}}}\, x^{\frac {10}{3}} \sqrt {x^{\frac {1}{3}} \left (b +a \,x^{\frac {2}{3}}\right )}\, F\left (\sqrt {\frac {a \,x^{\frac {1}{3}}+\sqrt {-a b}}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )+462 \sqrt {b \,x^{\frac {1}{3}}+a x}\, x^{\frac {10}{3}} a^{3} b -44 x^{\frac {8}{3}} \sqrt {x^{\frac {1}{3}} \left (b +a \,x^{\frac {2}{3}}\right )}\, a^{2} b^{2}-154 x^{\frac {10}{3}} \sqrt {x^{\frac {1}{3}} \left (b +a \,x^{\frac {2}{3}}\right )}\, a^{3} b +20 x^{2} \sqrt {x^{\frac {1}{3}} \left (b +a \,x^{\frac {2}{3}}\right )}\, a \,b^{3}+462 \sqrt {b \,x^{\frac {1}{3}}+a x}\, x^{4} a^{4}-90 x^{\frac {4}{3}} \sqrt {x^{\frac {1}{3}} \left (b +a \,x^{\frac {2}{3}}\right )}\, b^{4}}{195 x^{\frac {11}{3}} \left (b +a \,x^{\frac {2}{3}}\right ) b^{4}}\)	\(363\)

[In]

int(1/x^3/(b*x^(1/3)+a*x)^(1/2),x,method=_RETURNVERBOSE)

[Out]

-6/13*(b*x^(1/3)+a*x)^(1/2)/b/x^(7/3)+22/39*a*(b*x^(1/3)+a*x)^(1/2)/b^2/x^(5/3)-154/195*a^2*(b*x^(1/3)+a*x)^(1
/2)/b^3/x+154/65*(b+a*x^(2/3))*a^3/b^4/(x^(1/3)*(b+a*x^(2/3)))^(1/2)-77/65*a^3/b^4*(-a*b)^(1/2)*((x^(1/3)+1/a*
(-a*b)^(1/2))*a/(-a*b)^(1/2))^(1/2)*(-2*(x^(1/3)-1/a*(-a*b)^(1/2))*a/(-a*b)^(1/2))^(1/2)*(-x^(1/3)*a/(-a*b)^(1
/2))^(1/2)/(b*x^(1/3)+a*x)^(1/2)*(-2/a*(-a*b)^(1/2)*EllipticE(((x^(1/3)+1/a*(-a*b)^(1/2))*a/(-a*b)^(1/2))^(1/2
),1/2*2^(1/2))+1/a*(-a*b)^(1/2)*EllipticF(((x^(1/3)+1/a*(-a*b)^(1/2))*a/(-a*b)^(1/2))^(1/2),1/2*2^(1/2)))

Fricas [F]

\[ \int \frac {1}{x^3 \sqrt {b \sqrt [3]{x}+a x}} \, dx=\int { \frac {1}{\sqrt {a x + b x^{\frac {1}{3}}} x^{3}} \,d x } \]

[In]

integrate(1/x^3/(b*x^(1/3)+a*x)^(1/2),x, algorithm="fricas")

[Out]

integral((a^2*x^2 - a*b*x^(4/3) + b^2*x^(2/3))*sqrt(a*x + b*x^(1/3))/(a^3*x^6 + b^3*x^4), x)

Sympy [F]

\[ \int \frac {1}{x^3 \sqrt {b \sqrt [3]{x}+a x}} \, dx=\int \frac {1}{x^{3} \sqrt {a x + b \sqrt [3]{x}}}\, dx \]

[In]

integrate(1/x**3/(b*x**(1/3)+a*x)**(1/2),x)

[Out]

Integral(1/(x**3*sqrt(a*x + b*x**(1/3))), x)

Maxima [F]

\[ \int \frac {1}{x^3 \sqrt {b \sqrt [3]{x}+a x}} \, dx=\int { \frac {1}{\sqrt {a x + b x^{\frac {1}{3}}} x^{3}} \,d x } \]

[In]

integrate(1/x^3/(b*x^(1/3)+a*x)^(1/2),x, algorithm="maxima")

[Out]

integrate(1/(sqrt(a*x + b*x^(1/3))*x^3), x)

Giac [F]

\[ \int \frac {1}{x^3 \sqrt {b \sqrt [3]{x}+a x}} \, dx=\int { \frac {1}{\sqrt {a x + b x^{\frac {1}{3}}} x^{3}} \,d x } \]

[In]

integrate(1/x^3/(b*x^(1/3)+a*x)^(1/2),x, algorithm="giac")

[Out]

integrate(1/(sqrt(a*x + b*x^(1/3))*x^3), x)

Mupad [F(-1)]

Timed out. \[ \int \frac {1}{x^3 \sqrt {b \sqrt [3]{x}+a x}} \, dx=\int \frac {1}{x^3\,\sqrt {a\,x+b\,x^{1/3}}} \,d x \]

[In]

int(1/(x^3*(a*x + b*x^(1/3))^(1/2)),x)

[Out]

int(1/(x^3*(a*x + b*x^(1/3))^(1/2)), x)